Making My World (Almost) Real

One of my goals in high fantasy is to make my world as real as possible. High fantasy requires a lot of world-building. The author essentially becomes an architect of a new world, in addition to a story-teller.

My YA high fantasy series is set on the planet Tellia. I’ve always envisioned it being larger than earth, shrouded in a thick cloud-cover with no external light penetration, and teeming with bioluminescent life.

(I’ll admit when I saw the movie AVATAR back in 2008, I was not happy that James Cameron used all that bioluminescence on Pandora at night. I was afraid my book would sound like a Johnny-come-lately copy. But this aspect has been a part of my ideas for Tellia since 2003, so I’m sticking with it. Besides, on Tellia, there is NO light from their star, ever).

Most of the brighter white-light comes from a common medium-sized shrub called Ayastroh (light tree). Ayastroh are planted near the windows of buildings so the light can get in. They’re also potted inside of buildings. Every plant emits bioluminescence. Most fruit trees give off an orange-tinted light.

Another tree is used to tell time.

Tellia has its own calendar. Minutes and hours are equivalent to Earth minutes and hours. But Tellian days are 20 hours long. A week is 5 days (100 hours). A month is 25 days (500 hours). A segment is 8 months (4,000 hours). A year is 65 segments, with a bit of a quirk at the end, so it’s actually 259,980.387896312064 hours. Segment CalendarTime on Tellia is counted by the Dimertroh (time tree), which has a natural 20-hour bioluminescent cycle. Its color changes every five hours. It glows green during the five morning hours, white for the five day hours, blue for the five evening hours, and dark-purple during the five night hours.

In the final minutes of each segment, the Dimertroh dims to black. The new segment is counted at the beginning of the green cycle that follows. The Dimertroh also signals the end of a Tellian year. The last day of the 65th segment is shortened by nearly a full day (19 hours, ~37 minutes). The Dimertroh glows pink for the remaining ~23 minutes (0.387896312064 hours) of that last day. The New Year begins at the start of the green cycle that follows.

Daily Schedule

Ages on Tellia are counted by the segment rather than the year. A Tellian year is 29.657296 Earth years. An Earth year is 2.191538196 Tellian segments. So if you wanted to figure out what your age is in Tellian segments, you would multiply your age by 2.191538196. To make it easier, I’ve made a chart.

Segment to EY Conversion

Something else I had to figure out was exactly how big Tellia is as a planet. I have people traveling from here to there by foot and by ship in specific amounts of time. One thing was certain: I had a lot of research to do, and it would require more math.

My first question was, “How large is Tellia in the story itself?” If my main character, Ashura, walks from her city to the capital city, and if the trip takes two full days of travel, how far is the capital from her home? If it takes her 3 months to sail from her home to the Isle of Shifqu, how many kilometers is the trip? I drew a map of Tellia with meridian and latitudinal lines. I needed to determine how far apart the meridian lines are at the equator. So I had to look at sailing speeds and walking speeds.

Map of Tellia - 2-1 Scaled w LongLat

I wanted sailing to be fairly quick, but I wasn’t sure what decent sailing speeds are. I’ve always been enamored with clipper ships, so I did some research. Flying Cloud was a clipper that set a record by sailing from New York to San Francisco in 89 days, 8 hours in 1853 (full of people and cargo, mind you!). That record stood for 135 years until a few ships (built for speed and NOT carrying cargo!) beat Flying Cloud’s record. The anchor-to-anchor average speed for the 24,683 km journey was 11.51 kph.

On Tellia, I have ships being able to sail between meridian lines in 100 hours. I decided ships on Tellia would sail at an average of 12 kph. At that speed, a ship would cross 1,200 km of ocean in 100 hours. But I’ll make my meridian distances slightly smaller so it’s not such a neat number. I went with 1,198 km. On my map there are 42 meridian lines. So 42 * 1,198 km gives us Tellia’s equatorial circumference at 50,316 kilometers. (For reference, Earth’s is 40,075 km).

Now, the average human walking speed is 5 kph (3.10686 mph). If distance between meridians at the equator is 1,198 km, it will take 239.6 hours (11.83 days) to cover the distance while walking. However, I need to adjust for breaks and sleeping at night. No one can walk for 1,198 km without sleep. Travelers would walk for 10 hours/day max in Tellia’s 20 hour days (at least, that’s all the further I would want to walk). This will help me determine how far apart locations are on my map, and, therefore, how long it takes for my characters to walk there.

Now, because I know Tellia’s circumference is 50,316 km, I can calculate its diameter and radius. The formula for finding the circumference of a circle is C=πd. I need to divide the circumference by π to find the diameter.

50,316 km / 3.1415926535897932384626433832795 = 16,016.08 km diameter. That gives a radius of 8,008.04 km.

Now that I know Tellia’s mean radius, I need to determine its mass so the acceleration of gravity (g) will be nearly equal to the acceleration of gravity on Earth (g = 9.8 m/s2). I want to be able to walk on Tellia without sweating each time I try to lift my foot.

In order to figure this stuff out, I needed to do some physics. The acceleration of gravity formula is g=G*M/R2. G is the universal gravitational constant (6.67384×1011 N-m2/kg2). M is the mass. R2 is the square of the mean radius.

So, in order to calculate the acceleration of gravity (g) for Earth I needed to know earth’s radius and Earth’s mass. REarth = 6,371 km (6,371,000 m), so REarth2 = 40,589,641 km (40,589,641,000 m). MEarth = 5.97219×1024 kg.

g (m/s2) = ([G] 6.67384×1011 N-m2/kg2) * ([MEarth] 5.97219×1024 kg) / ([REarth2] 40,589,641,000 m).

The solution is 98,196,090,252,682,944,399,532,875.88821, but somehow that is equated to 9.8 m/s2. Don’t ask me how. I’m not a physicist. It might be different from what you’ll read on Wikipedia, but apparently G has been adjusted slightly over time. I picked one value for G and rolled with it.

I followed this by trying several calculations using different variables for Tellia’s possible mass. Tellia’s squared radius is RTellia2 = 64,128,706.509 km. When I calculate Tellia’s force of gravity with a mass of 9.4360602×1024 kg (which is 1.58 times the mass of Earth), I get this:

g (m/s2) = (6.67384×1011 N-m2/kg2) * (9.4360602×1024 kg) / (64,128,706,509.264 m). g = 9.8 m/s2.

The solution is actually 98,200,571,059,499,970,799,449,914, but I’m guessing it equates to 9.82 m/s2 just like Earth’s equation above. If Tellia’s mass were 1.6 times that of Earth, then g=9.94 m/s2.

I also calculated Tellia’s volume [V=4*π*R*R*R / 3] and surface area [A=4*π*R2].

Tellia’s mean diameter is 16,016.08 km. Earth’s is 12,742 km.

Tellia’s mean radius is 8,008.04 km. Earth’s is 6,371 km.

Tellia’s circumference is 50,316 km. Earth’s = 40,075 km.

Tellia’s solar rotation speed is 2,515.8 km/hr. Earth’s is 1,674.4 km/hr.

Tellia’s surface area is 805,865,093,014.879 km2. Earth’s is 510,072,000 km2.

Tellia’s volume is 2,151,133,237,173.37 km3. Earth’s is 1.08321×1012 km3.

Tellia’s mass is 9.4360602×1024 kg. Earth’s is 5.97219×1024 kg.

Tellia’s acceleration of gravity at its surface is 9.82 m/s2. Earth’s is 9.8 m/s2.

Of course, all of this assumes that I’ve done my math correctly. But math has never been one of my stronger skills. So if anyone finds a flaw in my calculations, I’d love to know about it.

I’ve done some work on Tellia’s atmosphere, too. From the outside, I want Tellia to look blue-ish (think Neptune!), so I need methane to be somewhat significant because it absorbs visible light on the red end of the spectrum. I imagine the upper Troposphere being subject to high wind speeds and persistent thick cloud-cover. From the inside, the sky would be grey-black swirling clouds, only visible because of the bioluminescent light, originating on the surface, that gets reflected back down.

Here’s what I came up with for the dry atmospheric composition: Nitrogen 65%; Oxygen 25.35%; Argon 3.23%; Methane 2.85%; Hydrogen 1.92%; Carbon Dioxide 1.0%; Helium 0.5%; Other gasses 0.15%.

I don’t have atmospheric pressure or thickness figured out. I’m going to go with the idea that it’s similar pressure to earth, if not a little heavier. For now, that math is beyond me.

So that’s that. World-building. It’s a lot of fun. It’s a lot of work. It’s frustrating at times, especially when you have to learn to calculate all the stuff above. But, in the end, I’m certain the work I’ve put into making my world as real as possible will help the story. That’s why I do it.

Christopher

Query Draft #100? Who’s Counting!

IMG_0760

Laughter is the best medicine, or so the proverb goes. I need a little laughter these days. I’ve been hard at work crafting the query letter for my novel, The Lesser Betrayal, and it has been exhausting. Worthwhile! But exhausting.

My brain is completely fried.

I’ve gone through countless drafts, revising minute details, or scrapping the whole thing and starting fresh. All the while I’ve tried to answer the questions Janet Reid (still can’t thank her enough!) gave me at the Midwest Writers Workshop this past July. Those questions are: (1) Who is the main character? (2) What does she want? (3) Who or what is blocking her? (4) What does she sacrifice?

It has been incredibly helpful – absolutely necessary – to focus on answering those questions. Yet, what I’ve learned so far is that answering the questions is one thing. Using them to craft a query letter is quite another.

Admittedly, my biggest problem is trying to add too much detail to the query. I’ve done my best to cut it down to the necessary stuff. But even then, I’ve had to reword each sentence hundreds of times. I’ve had to save it, close it, and set it aside at times in order to clear my head.

It’s mind-boggling to craft a query letter. But I think I might be getting close to a decent product.

Below is the most recent draft at 292 words. It’s just the guts of the query, not the full letter.

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Long ago, Ashura’s ancestors were betrayed by the immortal father of all people and cursed with mortality. Now, Tellia is a world divided between mortals and immortals. And divisions among the mortals run deep.

Ashura has trained to be warrior since she was fifteen segments old. Like all women in the Queendom of Hoqra, she will guard her home from the kingdoms that want to destroy the only land where women rule. When her older sister is killed in yet another invasion, Ashura’s one desire is to protect the family she has left.

Ashura’s plans are ruined when she’s claimed by a master of the powerful Order of Shifqu and forced to leave her family. Yet, in the Order, Ashura discovers another way to protect her family. If Ashura can help the Order break the curse of mortality, she’ll do more than protect them: she’ll save them from death.

Ashura’s mission is to kill the latest-born princess of the immortal Children of Ainariel. When she is captured in the middle of the attempted assassination, she expects to be executed. Instead, Ashura is forgiven and shown kindness. The benevolence of her enemies causes Ashura to question her people’s version of the curse.

Then, Ashura is healed of the curse and given immortality. She realizes her people have been wrong about everything. Ashura’s enemies become her friends.

When the Order of Shifqu attacks the princess’s village in force, Ashura’s former friends become her enemies. Ashura must choose to protect the Children of Ainariel, or let the Order kill them. If she fights the Order of Shifqu, she’ll sacrifice ever seeing her family again. When every choice she has is a betrayal of some kind, the best Ashura can do is choose the lesser betrayal.

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I’m going to sit on this one for a while. I’m going to read it again in a day or two and see how I might be able to tweak it or clarify something. Writing a query letter is a LOT of work. For me, it’s proved to be the most difficult part of the publishing process. But I know when I get it right, it’ll be worth all the brain-frying effort I’ve put into it.

Christopher